SOLUTION: graph the ellipse x^2+4y^2=64 - Algebra Homework Help x^2 + 4y^2 = 64 subtract x^2 from both sides to get: 4y^2 = 64 - x^2 divide both sides by 4 to get: y^2 = (64-x^2) 4 take square root of both sides to get: y = + - you could simplify further but it's not necessary you would graph 2 equations first equation would be: y = and second equation would be: y = - shown below:
SOLUTION: x x+8 - 8 x-8 = x^2+64 x^2-64 - Algebra Homework Help Second we find the values of x for which the denominator is zero: Solve the equation:, setting to zero each factor and get: x=8 and x=-8 These values can't be roots for our equation Now solve the equation: , multiply both sides by (x-8)(x+8) => => =>x=-8 We reject this root and say that the equation doesn't have solution on the real numbers set
SOLUTION: Please help me solve this equation x^4 + 12x^2 -64 = 0 x^4 + 12x^2 -64 = 0 (here you must know how we make factors i e splitting of the middle term if you might not know then please contact me again ,,and i will explain to you) x^4 + (16-4)x^2 -64 = 0 by solving brackets we get x^4 +16x^2 -4x^2 -64 = 0 taking common from first two and last two variables we get x^2(x^2 +16) -4 (x^2 +16)= 0
SOLUTION: Which expression is equivalent to 64 - x^2? A. (8-x)(8-x) B . . . should be (8-x) * (8+x) multiply them out and you get: 8 * 8 + 8 * x - x * 8 - x * x simplify to get 64 + 8x - 8x - x^2 combine like terms to get 64 - x^2 the + 8x and the - 8x cancel each other out you are using the distributive law of multiplication that says (a + b) * (c + d) = a * c + a * d + b * c + b * d