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  • std::future - cppreference. com
    The class template std::future provides a mechanism to access the result of asynchronous operations: An asynchronous operation (created via std::async, std::packaged_task, or std::promise) can provide a std::future object to the creator of that asynchronous operation
  • std::future lt;T gt;:: future - en. cppreference. com
    Constructs a std::future with the shared state of other using move semantics After construction, other valid ( ) == false 3) std::future is not CopyConstructible
  • std::shared_future lt;T gt;::shared_future - cppreference. com
    2) Constructs a shared future that refers to the same shared state, if any, as other 3,4) Transfers the shared state held by other to * this After the construction, other valid ( ) == false , and this - > valid ( ) returns the same value as other valid ( ) would have returned before the construction
  • How to suppress Pandas Future warning? - Stack Overflow
    When I run the program, Pandas gives 'Future warning' like below every time D:\Python\lib\site-packages\pandas\core\frame py:3581: FutureWarning: rename with inplace=True will return None from pandas 0 11 onward " from pandas 0 11 onward", FutureWarning) I got the message, but I just want to stop Pandas showing such message again and again
  • std::experimental:: make_ready_future - Reference
    Creates a shared state of type V that is immediately ready, with the result constructed from std:: forward < T > (value), then returns a std::experimental::future associated with that shared state
  • Cannot build CMake project because Compatibility with CMake lt; 3. 5 has . . .
    In this case it does work In general, it probably doesn't I'm wondering how this break in backwards compatibility should in general be navigated Perhaps installing a previous version of CMake is the only way that always works? That would mean that each project in the future should specify the CMake version on which it should be built –
  • std::future lt;T gt;::valid - cppreference. com
    It is valid to move from a future object for which valid() is false Contents 1 Parameters; 2 Return value;




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